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8y^2-6y-20=0
a = 8; b = -6; c = -20;
Δ = b2-4ac
Δ = -62-4·8·(-20)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*8}=\frac{-20}{16} =-1+1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*8}=\frac{32}{16} =2 $
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